Q=m.c.delta T
C=Q/m.delta t
Dik=
Massa = 0,5
delta T =120
Q= 23,4kj /23400j
23400/0.5 x 120 = 23400/60
=390 j/kg.C
Tembaga
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Q=m.c.delta T
C=Q/m.delta t
Dik=
Massa = 0,5
delta T =120
Q= 23,4kj /23400j
23400/0.5 x 120 = 23400/60
=390 j/kg.C
Tembaga