Jawaban:
[tex] < AOC + < BOC = 90° \\ 6x° + 4 °+ 5x °+ 9 °= 90° \\ 11x° + 13° = 90° \\ 13x = 90° - 13° \\ x = \frac{77°}{11°} \\ x = 7° \\ \\ sudut \: AOC \\ 6x °+ 4° \\ 6(7°) + 4° \\ 42° + 4 °\\ 46° \: (c)[/tex]
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Jawaban:
[tex] < AOC + < BOC = 90° \\ 6x° + 4 °+ 5x °+ 9 °= 90° \\ 11x° + 13° = 90° \\ 13x = 90° - 13° \\ x = \frac{77°}{11°} \\ x = 7° \\ \\ sudut \: AOC \\ 6x °+ 4° \\ 6(7°) + 4° \\ 42° + 4 °\\ 46° \: (c)[/tex]