PEMBAHASAN
Dimensi Tiga
Kubus
r = 4 cm
O tengah HF
Perhatikan ∆BFO
siku di F
HF = r√2
FO = 1/2 HF = 1/2 r√2
BO = 1/2 r√6
Sudut antara BF dan bidang BEG adalah sudut FBO.
∠(BF , BEG) = ∠FBO = B
sin B = FO/BO
sin B = (1/2 r√2)/(1/2 r√6)
sin B = 1/√3
sin B = 1/3 √3
cos B = BF/BO
cos B = r/(1/2 r√6)
cos B = 1/3 √6
tan B = FO/BF
tan B = (1/2 r√2)/r
tan B = 1/2 √2
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Verified answer
PEMBAHASAN
Dimensi Tiga
Kubus
r = 4 cm
O tengah HF
Perhatikan ∆BFO
siku di F
HF = r√2
FO = 1/2 HF = 1/2 r√2
BO = 1/2 r√6
Sudut antara BF dan bidang BEG adalah sudut FBO.
∠(BF , BEG) = ∠FBO = B
sin B = FO/BO
sin B = (1/2 r√2)/(1/2 r√6)
sin B = 1/√3
sin B = 1/3 √3
cos B = BF/BO
cos B = r/(1/2 r√6)
cos B = 1/3 √6
tan B = FO/BF
tan B = (1/2 r√2)/r
tan B = 1/2 √2