Question

Pakai penjelasan dan caranya ya kakak

Answer 1

Penjelasan dengan langkah-langkah:

maaf kalau salah

√2+√2+√2+... = a

pangkatkan

2 + √2+√2.... = a^2

2 + a = a^2

a^2 - a - 2 = 0

nilai a dapat bernilai -1 atau 2

Answer 2

Verified answer

[tex] \sqrt{2 + \sqrt{2 + \sqrt{2 + \sqrt{...} } } } = [/tex]

[tex] \frac{1 + \sqrt{1 + 4(2)} }{2} = [/tex]

[tex] \frac{1 + \sqrt{1 + 8} }{2} = [/tex]

[tex] \frac{1 + \sqrt{9} }{2} = [/tex]

[tex] \frac{1 + 3}{2} = [/tex]

[tex] \frac{4}{2} = [/tex]

[tex]2[/tex]