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y' = 4{4 + √(x² + x)}^3 (1/2)(x² + x)^(-1/2) (2x + 1)
= (4x + 2)(x² + x)^(-1/2) {4 + √(x² + x)}^3
2) y = {3 - (3x - 1)²}^3
y' = 3{3 - (3x - 1)²}² (- 2(3x - 1)(3))
= (- 18x + 18){3 - (3x - 1)²}²
3) y = {(4x² + x)² + 5}^3
y' = 3{(4x² + x)² + 5}² (2(4x² + x)(8x + 1))
= 6(4x² + x)(8x + 1){(4x² + x)² + 5}²
^ = pangkat