pada trapesium abcd disamping. panjang bc = 15 cm ad = 13 cm ae = 5 cm dan cd 4 cm hitunglah luas abcd #copyreport #asalreport
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Penjelasan dengan langkah-langkah:
de = √(ad)² - (ae)²
de = √13² - 5²
de = √169 - 25
de = √144
de = 12 cm
bf = √(bc)² - (cf)²
karena cf = de maka
bf = √15² - 12²
bf = √225 - 144
bf = √81
bf = 9 cm
ab = ae + ef + bf
ab = 5 cm + 4 cm + 9 cm
ab = 18 cm
L abcd = (cd + ab)/2 x de
L abcd = (4 + 18)/2x 12
= 11 x 12
= 132 cm²
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DE = √13² - 5²
= √(13(13) - (5(5)
= √169 - 25
= √144
= √(12(12)
= √12²
= 12 CM
BF = √15² - 12²
= √(15(15) - (12(12)
= √225 - 144
= √81
= √9²
= 9 CM
AB = (5 + 4 + 9)
= (9 + 9)
= 18 CM
MAKA :
L = (4 + 18)/2(12)
= 22/2(12)
= 11/1(12)
= 11(12)
= 132 CM²