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T1 = 20°C
L = 20 m
T2 = 80°C
ρ besi = 0,000011/°C
ΔL = ...?
ΔL = L . ρ besi . ΔT
ΔL = 20 m. 0,000011/°C. (80°C - 20°C)
ΔL = 20. 0,000011. 60 m
ΔL = 0,0132 m
ΔL = 13,2 mm
Jadi, pertambahan panjang kawat itu 0,0132 m atau 13,3 mm