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Lo= 200 cm
ΔL= 200,24-200= 0,24 °C
Δt= 100-0= 100°C
Dit:
α= ..?
Penye:
α= ΔL/(Lo.Δt)
α= 0,24/(200×100)
α= 0,24/20000
α= 0,000012 /°C
ΔL = 200,24 - 200 = 0,24 °C
Δt = 100 - 0 = 100°C
Ditanya = α ..?
Jawab =