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beda = 5
jika f(10) = 52
5x + ... = 52
5×10 + ... = 52
50 + ... = 52
... = 2
f(x) = 5x + 2
cek :
f(10) = 5 × 10 + 2 = 52
maka
f(1) = 5 × 1 + 2 = 7
jadi, a = 7