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Verified answer
N(S) = 6a) n(A) = 4,5,6 = 3
n(P) = 3/6 = ½
frekuensi = ½ × 1.200 = 600 kali
b) n(A) = 3,5 = 2
n(P) = 2/6 = ⅓
frekuensi = ⅓ × 1.200 = 400 kali
c) -
B. 1/3. 1200 = 400 kli
C. -
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