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= 36
a.berjumlah 8
n(a) = { ( 2,6) (6,2) ( 3,5) ( 5,3) (4,4) }
= 5
peluang
p(A) = 5/36
b.berjumlah lebih dari 7
n(a) = { ( 2,6) (6,2) ( 3,5) ( 5,3) (4,4) ( 4,5) (5,4) (3,6) (6,3) ( 5,5) (6,4) (4,6) (6,6)}
= 14
peluang
p(A) = 14/36
= 7/18
a. berjumlah 8 = (2,6),(3,5),(4,4),(5,3),dan(6,2) >> n = 5
peluang =
b. berjumlah lebih dari 7 (8-12) = (2,6),(3,5),(4,4),(5,3),(6,2),(3,6),(4,5),(5,4),(6,3),(4,6),(5,5),(6,4),(5,6),(6,6) >> n = 14
peluang =
Semoga membantu :)