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=3a+b=5
f(1)=-3 f(x)=a.1+b=-3
=1a+b=-3
3a+b=5 dikurangi 1a+b=-1 jadi =4a
3a+b=5
3(4)+b=5
7+b=5
b=5-7
b=-2
1a+b=-3
1.4+b=-3
4+b=-3
b=-3-4
b=7
setahu sya sih gtu, smoga bnar
x=3→ 3a+b =5
x=1→a+b =-3
________ -
3a-a =5-(-3)
2a =8
a =4
a=4 → 3a+b = 5
3.4+b =5
12+b =5
b = 5-12
b=-7