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Verified answer
F(1) = a+b=3f(2)=2a+b=5
lakukan eliminasi
2a + b = 5
a + b = 3
________-
a = 2
maka
a + b = 3
2 + b = 3
b = 1
bentuk fungsi :
f(x) = 2x + 1
f(-2) = -2a + b
= -2(2) + 1
= -4 + 1
= -3
f(1) = a + b
3 = a + b
f(2) = 2a + b
5 = 2a + b
dieliminasikan
2a + b = 5
a + b = 3
---------------- --
a = 2
a + b = 3
2 + b = 3
b = 3 - 2
= 1
A. a = 2
b = 1
B. f(x) = ax + b
f(x) = 2x + 1
C. f(x) = 2x + 1
f(-2) = 2 × (-2) + 1
= -4 + 1
= -3
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