Question

p = -3 , Q = 4, r = -8

hitunglah

a. p + Q + r
b. p - Q + r
c. p - Q - r
d. -p - Q + r

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Answer 1

Verified answer

Kelas : VIII

Mapel : Matematika

Bab : I - Operasi Bentuk Aljabar

Kode : 8.2.1

[tex] \\ [/tex]

• p = -3
• Q = 4
• r = -8

Subtitusi saja ke soal

Sub A

[tex] p+Q+r [/tex]

[tex] = (-3)+4+(-8) [/tex]

[tex] = -3+4-8 [/tex]

[tex] = 1-8 [/tex]

[tex] = \boxed{ -7 } [/tex]

Sub B

[tex] p-Q+r [/tex]

[tex] = (-3)-4+(-8)[/tex]

[tex] = -3-4-8[/tex]

[tex] = -7-8[/tex]

[tex] =\boxed{ -15}[/tex]

Sub C

[tex] p-Q-r [/tex]

[tex] = (-3)-4-(-8)[/tex]

[tex] = -3-4+8[/tex]

[tex] = -7+8[/tex]

[tex] =\boxed{ 1}[/tex]

Sub D

[tex] -p-Q+r [/tex]

[tex] = -(-3)-4+(-8)[/tex]

[tex] = 3-4-8[/tex]

[tex] = -1-8[/tex]

[tex] =\boxed{ -9}[/tex]

[tex] \\ [/tex]

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Answer 2

Jawab:
[a]  = -7
[b]  = -15
[c]  = 1
[d]  = -9

Penjelasan dengan langkah-langkah:
Diketahui
p = -3, q = 4, r = -8

Hitunglah
[a]  p+q+r = -3+4+(-8) = 4-3-8 = 1-8 = -(8-1) = -7
[b]  p-q+r = -3-4+(-8) = -(3+4)-8 = -(3+4+8) = -15
[c]  p-q-r = -3-4-(-8) = -(3+4)+8 = -7+8 = 8-7 = 1
[d]  -p-q+r = -(-3)-4+(-8) = -(4+(-3))-8 = -1-8 = -(1+8) = -9

(xcvi)