Question

Despejar "N" en:

Q+N2
Q = -------------------
N2 - P

A) √ P + 1/ Q-1
B) √ Q(Q-l)/ P+l
C) √ Q(P + 1)
D) √ Q(P+l)/ Q-l
E) √ P(Q+l)/P-1

Answer 1

Q (n^2 -p) = q+ n^2
qn^2 -pq = q + n^2
qn^2 -n^2 = q +pq
n^2(q-1) = q+pq
n^2 = q(1+p)/(q-1)
n = raizde( q(1+p)/(q-1))

Seria la alternativa d :)