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a) 2C₁₅H₃₂+31O₂→30CO+32H₂O
b)C₉H₂₀+14O₂→9CO₂+10H₂O
c)C₁₁H₂₄+6O₂→11C+12H₂O
2. C5H10 penten
2 C15H32 + 31 O2 ---> 30 CO + 32 H2O
C9H20 + 14 O2 ---> 9 CO2 + 10 H2O
C11H24 + 6 O2 ---> 11C + 12 H2O
2/
Ogólny wzór alkenów CnH2n
M = 70 u
MC = 12 u
MH = 1 u
12 * n + 1 * 2 * n = 70
14 * n = 70
n = 5
wzór alkenu C5H10