Oblicz,jaka ilosc wody mineralnej niegazowanej o zawartosci 9,73 mg/dm3 sodu trzeba wypic,aby zaspokoic dzienne zapotrzebowanie na sód ( 1500 mg/osobe)
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d=m/v / *v
d*v=m /:d
v=m/d
v=1500mg/9,73mg/dm3 =( 1500mg * dm3 )/9,73 mg =154,2dm3