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z2= 3+5i
z3= 4-i
z1-z3 = (-2+i) -( 4-i)
= -2+i -4+i
= -6+2i
(z1+z2)×(z3)
= (-2+i + 3+5i)(4-i)
=(1+6i)(4-i)
= 4-i +24i - 6i²
= 4 +23i +6
= 10+23i