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a)
H- 1u
S- 32u
O-16u
m= 1*2+32+16*3=82u
82u-100%
32-x
x= ok. 39%----siarka
x= 16*3 *100/ 82=4800/82=ok. 59%----tlen
b)
stosunek 32:48 po skróceniu : 2:3
c) tl.siarki (IV)
SO2
s- 32u
O- 16 u
16*2=32u
32:32 po skróceniu 1:1 ----stosunek