Reaksi setara
2H2O - > 2H2 + O2
Mol air = 9000/18 = 500 mol
Mol O2
Volume saat 0°C dan 1 atm, artinya volume pada keadaan standar
Volume = mol x 22, 4
Volume = 250 x 22,4
Volume = 5600 L
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Reaksi setara
2H2O - > 2H2 + O2
Mol air = 9000/18 = 500 mol
Mol O2
Volume saat 0°C dan 1 atm, artinya volume pada keadaan standar
Volume = mol x 22, 4
Volume = 250 x 22,4
Volume = 5600 L