Odpowiedź:
x = [tex]\frac{3 + 6 + 12 + 15}{4} = \frac{36}{4} = 9[/tex]
ρ² = [tex]\frac{( 3 - 9)^2 + (6 - 9)^2 + (12- 9)^2 + (15- 9)^2}{4} =\frac{36 + 9 + 9 + 36}{4} = \frac{90}{4} = \frac{9}{4} * 10[/tex]
więc
ρ = [tex]\sqrt{\frac{9}{4}*10 } = \frac{3}{2} \sqrt{10} = 1,5\sqrt{10}[/tex]
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Odpowiedź:
x = [tex]\frac{3 + 6 + 12 + 15}{4} = \frac{36}{4} = 9[/tex]
ρ² = [tex]\frac{( 3 - 9)^2 + (6 - 9)^2 + (12- 9)^2 + (15- 9)^2}{4} =\frac{36 + 9 + 9 + 36}{4} = \frac{90}{4} = \frac{9}{4} * 10[/tex]
więc
ρ = [tex]\sqrt{\frac{9}{4}*10 } = \frac{3}{2} \sqrt{10} = 1,5\sqrt{10}[/tex]
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Szczegółowe wyjaśnienie: