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ΔL = L₁ - Lo
= 50,05 cm - 50 cm
= 0,05 cm
Δt = t₁ - to
= 110 °C - 10 °C
= 100 °C
Ditanyakan : α
Penyelesaian : α = ΔL : (Lo . Δt)
= 0,05 : (50 . 100)
= 0,05 : 5000
= 0,00001/°C