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α = 0,000011/C
To = 30 C
Lo = 50 cm
L = 50,011 cm
Ditanyakn : T ?
Dijawab :
ΔT = ΔL/αxLo
(T-30) = (50,011-50) / (0,000011x50)
(T-30) = 0,011/0,00055
(T-30) = 20
T = 20 + 30
T = 50 C
Jadi suhu akhir = 50 C
adapun kenaikan suhu = 50 - 30 = 20 C