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t1= 20 derajat celsius
t2= 40 derajat celcius
α= 0,000011 /oC
ditanya Lt=...
jawab:
Δt= t2-t1
= 40 oC-20oC= 20oC
Lt= lo(1+α×Δt)
= 50m(1+0,000011/oC×20oC)
= 50m(1+ 0,00022)
=50m(1,00022)
=50,011 cm