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Lo = 1 meter
t1 = 30 derajat celcius
t2 = 130 derajat celcius
α = 0,000011/derajat celcius
Ditanyakan
L = ..... ?
Δt = t2 - t1
Δt = 130 - 30
Δt = 100
L = Lo ( 1 + α . Δt )
L = 1 ( 1 + 0,000011 . 100 )
L = 1 ( 1 + 0,0011 )
L = 1 ( 1,0011 )
L = 1,0011 m