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L0 = 1 m
t1 = 30oC
t2 = 130oC
Δt = 100oC
α = 0,000011/oC
Ditanyakan : Lt =..???
jawab :
ΔL = Lo . α . Δt
= 1 . 0,000011 . 100
=0,0011
Lt = L0 + ΔL
= 1 + 0,0011
= 1,0011 m
Δt =
1,1×10⁻⁵/°C
Δt)
×10⁻⁵.
×10⁻³)
×10⁻³
(C)