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α = 0,00002/°C
Δt = t₁ - to = 70°C - 20°C = 50°C
Ditanyakan : L₁ (Lo + ΔL)
Penyelesaian : ΔL = α . Lo . Δt
= 0,00002/°C . 40 cm . 50°C
= 0,04 cm
L₁ = Lo + ΔL
= 40 cm + 0,4 cm
= 40,04 cm