[tex]\frac{2(x-3)}{x-4}-\frac{x-1}{x-4}-\frac{x+2}{x}=\\\\\frac{2x-6-x+1}{x-4}-\frac{x+2}{x}=\\\\\frac{x-5}{x-4}-\frac{x+2}{x}=\\\\\frac{x^2-5x-(x-4)(x+2)}{x(x-4)}=\\\\\frac{-3x+8}{x(x-4)}\\[/tex]
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[tex]\frac{2(x-3)}{x-4}-\frac{x-1}{x-4}-\frac{x+2}{x}=\\\\\frac{2x-6-x+1}{x-4}-\frac{x+2}{x}=\\\\\frac{x-5}{x-4}-\frac{x+2}{x}=\\\\\frac{x^2-5x-(x-4)(x+2)}{x(x-4)}=\\\\\frac{-3x+8}{x(x-4)}\\[/tex]