Obliczyć ile waży
a)1 mol amoniaku
b)2 mole Cu20
c) 6 moli wodoru
d) 2 atomy wodoru
proszę o pilne rozwiązanie
1 mol CH3 = 15g\mol
2 mol CuO2 =64+32=96*2=192g\mol
6mol h=1 mol H to 2g-H= 6*2=12g\mol
2 atomy H = 2*1=2u
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1 mol CH3 = 15g\mol
2 mol CuO2 =64+32=96*2=192g\mol
6mol h=1 mol H to 2g-H= 6*2=12g\mol
2 atomy H = 2*1=2u