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a) Fe2S3
n(Fe)=2*5=10mol
n(S)=3*5=15mol
b)Ca3(PO4)2
W tym przypadku caly nawias trzeba pomnozyc przez dwa, czyli:
n(Ca)=3*2=6mol
n(P)=2*2=4mol
n(O)=2*4*2=16mol