Oblicz,ile gramów wody należy dodać do 250 g 6-procentowego octu, by otrzymać 3-procentowy roztwór
Cp=ms/mr*100%
250g 6% ...................3-0=3.....................3%xg 0%....................... 6-3=3250/x = 3/33x = 250*3x = 250g wody
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mr = 250 g
ms = ?
Cp=ms/mr*100%
ms=mr*Cp/100%= 250*6/100=15ms = 15 g
Cp = 3%
ms = 15 g
mr = ?
3% = 15g*100 / mr
mr = 500 g
500g-250 g = 250 g H20
250g 6% ...................3-0=3
.....................3%
xg 0%....................... 6-3=3
250/x = 3/3
3x = 250*3
x = 250g wody