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MHCOOH=12+2+32=46g/mol
46g----100%
12g----x
x=26,1% tyle to jest wegiel
Licze na najlepsze:).
mHCOOH=12u+2*1u+2*16u=46u
46g HCOOH-------100%
12g węgla---------x%
x=26,1% węgla
MHCOOH=12+2+32=46g/mol
46g - 100%
12g - x
x = 26,1% tyle jest wegla