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kwas masłowy to inaczej kwas butanowy czyli C3H7COOH
m=3*12u+7*1u+12u+2*16u+1u=88u
mC=4*12u=48u
%C=48u*100%/88u≈55%
mH=8u
%H=8u*100%/88u≈9%
mO=32u
%O=32u*100%/88u≈36%
powinno byc dobrze ;)
mcz= 4*12+8*1+2*16=48+8+32=88
88--100%
48---x
x= 48*100/88=54
opd. zawartośc wegla w kwasie masłowym wynosi 54 %