oblicz zawartośc procentową w tlenku węgla IV
mCO2=12u+32u=44u
%C = (12/44)*100% = 27,3%
%O = (32/44)*100% = 72,7%
m CO₂ = 44u
m C = 12u
m O₂ = 2·16u = 32u
%C
44u ----- 100%
12u ----- X%
X = (12u · 100%) : 44u ≈ 27,27%
%O
32u ----- Y%
Y = (32u · 100%) : 44u ≈ 72,73%
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mCO2=12u+32u=44u
%C = (12/44)*100% = 27,3%
%O = (32/44)*100% = 72,7%
m CO₂ = 44u
m C = 12u
m O₂ = 2·16u = 32u
%C
44u ----- 100%
12u ----- X%
X = (12u · 100%) : 44u ≈ 27,27%
%O
44u ----- 100%
32u ----- Y%
Y = (32u · 100%) : 44u ≈ 72,73%