Oblicz zawartośc procentową w kwasie azotowym (V).
mHNO3=1u+14u+3*16u=63u
%H = (1/63)*100% = 1,6% H
%N = (14/63)*100% = 22,2% N
%O = (48/63)*100% = 76,2% O
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mHNO3=1u+14u+3*16u=63u
%H = (1/63)*100% = 1,6% H
%N = (14/63)*100% = 22,2% N
%O = (48/63)*100% = 76,2% O