a) mAlCl3=27u+106,5=133,5u%Al = (27/133,5)*100% = 79,8%%Cl = (106,5/133,5)*100% = 20,2%b) mNa2SO4=46u+32u+64u=142u%Na = (46/142)*100% = 32,4%%S = (32/142)*100% = 22,5%%O = (64/142)*100% = 45,1%c) mPb(NO3)2=207u+28u+96u=331u%Pb = (207/331)*100% = 62,5%%N = (28/331)*100% = 8,5%%O = (96/331)*100% = 29,0%
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a) mAlCl3=27u+106,5=133,5u
%Al = (27/133,5)*100% = 79,8%
%Cl = (106,5/133,5)*100% = 20,2%
b) mNa2SO4=46u+32u+64u=142u
%Na = (46/142)*100% = 32,4%
%S = (32/142)*100% = 22,5%
%O = (64/142)*100% = 45,1%
c) mPb(NO3)2=207u+28u+96u=331u
%Pb = (207/331)*100% = 62,5%
%N = (28/331)*100% = 8,5%
%O = (96/331)*100% = 29,0%