mSr(OH)2=88u+2*16u+2*1u=122 u
Stosunek mas:
mSr:mO:mH=88:32:2=44:16:1
Zawartość procentowa pierwiastków:
88u---x%
122u---100%
x=72,13%Sr
32u---x%
x=26,23%O
100%-(72,13%+26,23%)=1,64%H
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mSr(OH)2=88u+2*16u+2*1u=122 u
Stosunek mas:
mSr:mO:mH=88:32:2=44:16:1
Zawartość procentowa pierwiastków:
88u---x%
122u---100%
x=72,13%Sr
32u---x%
122u---100%
x=26,23%O
100%-(72,13%+26,23%)=1,64%H