Oblicz zawartość procentowa zelaza w tlenku zelaza(III)
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Oblicz zawartość procentowa zelaza w tlenku zelaza(III)
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m Fe₂O₃ - 2 x 56u + 3 x 16u = 160u
m Fe = 2 x 56u = 112u
m O = 3 x 16u = 48u
% Fe = 112u/160u x 100% = 70%
O O = 48u/160u x 100% = 30%
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Pozdrawiam :)
Tlenek żelaza III - Fe2O3
mFe = 55,8u
mO = 16u
masa związku = 2*55,8u + 3*16u = 159,6
masa żelaza w związku = 2*mFe = 2*55,8u = 111,6u
zawartość procentowa = 69,92%