Oblicz zawartość procentową wody w hydracie Na2SO x 10H2O (mNa = 32u, mS-32u, mO=16u, mH-1u).
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mNa2SO4*10H2O=2*23u+32u+4*16u+10(2u+16u)=322u
m10H2O=180u
%H2O = (180/322)*100% = 55,9%
mNa2SO4*10H2O=2*23u+32u+4*16u+20*1u+10*16u=142u+180u=322u
%H2O=180u*100%/322u≈55,9%