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m = 2*1u + 12u + 3*16u = 14u + 48u = 62u
m(wodoru) = 2u
2u/62u * 100% = 3%
kwas fosforowy V: H₃PO₄
m=3u + 4*16u + 31u = 98u
m(wodoru) = 3u
3u/98u * 200% = 3%
MmolH2CO3=62g/mol
MmolH=1g/mol 1g*2=2g
100%-62g
x% -- 2g
x=3,22% - wodoru
H3PO4
MmolH3PO4=98g/mol
MmolH=1g/mol 1g*3=3g
100%- 98g
x% -- 3g
x=3,06%- wodoru
62g-100%
2g-x%
x=2g*100%/62g=3.2%
masa H3PO4=3*1+31+16*4=98
98g-100%
3g-x&
x=300/98g=3.06%