wzór: H2CO3
masa : 1+1+12+16+16+16=62g
masa C: 12g
12/62 x 100%=19,35%
mH2CO3 = 2 * 1u + 12u + 3*16u = 2u+12u+ 48u = 62u
mC = 12u
62u ---- 100%
12u ---- x
______________
62x=1200 / :62
x=19,35≈20%
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wzór: H2CO3
masa : 1+1+12+16+16+16=62g
masa C: 12g
12/62 x 100%=19,35%
mH2CO3 = 2 * 1u + 12u + 3*16u = 2u+12u+ 48u = 62u
mC = 12u
62u ---- 100%
12u ---- x
______________
62x=1200 / :62
x=19,35≈20%