mCa(HCO3)2=40u+2*1u+2*12u+6*16u=162 u
WĘGIEL
24u---x%
162u---100%
x=14,81%C
TLEN
96u---x%
x=59,26%O
WAPŃ
40u---x%
x=24,69%Ca
WODÓR
2u---x%
x=1,23%H
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mCa(HCO3)2=40u+2*1u+2*12u+6*16u=162 u
WĘGIEL
24u---x%
162u---100%
x=14,81%C
TLEN
96u---x%
162u---100%
x=59,26%O
WAPŃ
40u---x%
162u---100%
x=24,69%Ca
WODÓR
2u---x%
162u---100%
x=1,23%H