Question

Oblicz zawartość procentową węgla i wodoru w propynie.

Answer 1

Propyn- C3H4

mC3H4=3*12u+4*1u=40u

36u-x%
40u-100%
x=36u*100%/40u
x=90%C

100%-90%=10%H

Answer 2

Wzór propynu: C3H4 
Mmolowa C3H4 = 12 * 3 + 4= 40 g/mol 
Mwodoru = 4 g/mol 
%H = (4g/mol / 40 g/mol ) *100%=10%
Mwęgla = 12g/mol * 3 = 36g/mol
%C = (36g/mol / 40 g/mol) * 100% = 90%