Oblicz zawartość procentową tlenu w HNO2
masa HNO2= 1x1u+1x14u+2x16u=47u
c% o= 32u/47 x 100%=68%
H - 1 · 1 =1
N -1·14=14
O - 2 ·16=32
1 + 14 + 32 =47
Cp= 32/47 · 100%
Cp = 3200%/47 = 68%
/ - zapisz w ułamku
mHNO2=1u+14u+2*16u=47u
%O=32u/47u * 100%
%O=68,1%
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masa HNO2= 1x1u+1x14u+2x16u=47u
c% o= 32u/47 x 100%=68%
H - 1 · 1 =1
N -1·14=14
O - 2 ·16=32
1 + 14 + 32 =47
Cp= 32/47 · 100%
Cp = 3200%/47 = 68%
/ - zapisz w ułamku
mHNO2=1u+14u+2*16u=47u
%O=32u/47u * 100%
%O=68,1%