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S=32u
O=16u
H=1u
Masa tlenu w H₂SO₃=48u
Masa H₂SO₃=2×1u+32u+3×16u=34u+48u=82u
%S=32/82×100%≈39%
%O=48/82*100%≈58,5%
O3/H2SO3*100%= 48u/82u*100%= 58,54%