Oblicz zawartość procentową (procent masy) pierwiastków chemincznych w wodorotlenku wapnia. ( Zadanie na jutro )
mCa(OH)2=40u+2*16u+2*1u=74u
%Ca = (40/74)*100% = 54%
%O = (32/74)*100% = 43%
%H = (2/74)*100% = 3%
%Ca=40u/74u * 100%
%Ca=54%
%O=32u/74u * 100%
%O=43%
%H=2u/74u * 100%
%H=3%
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mCa(OH)2=40u+2*16u+2*1u=74u
%Ca = (40/74)*100% = 54%
%O = (32/74)*100% = 43%
%H = (2/74)*100% = 3%
mCa(OH)2=40u+2*16u+2*1u=74u
%Ca=40u/74u * 100%
%Ca=54%
%O=32u/74u * 100%
%O=43%
%H=2u/74u * 100%
%H=3%