Odpowiedź:
mC₁₂H₂₂O₁₁=12*12u+22*1u+11*16u=144u+22u+176u=342u
mC=12*12u=144u
342u - 100%
144u - x%
x=(144u*100%):342u≈42,1% węgla
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Odpowiedź:
mC₁₂H₂₂O₁₁=12*12u+22*1u+11*16u=144u+22u+176u=342u
mC=12*12u=144u
342u - 100%
144u - x%
x=(144u*100%):342u≈42,1% węgla