mC3H6=3*12u+6*1u=42u
36u---x%
42u---100%
x=85,71%C
mC6H10=6*12u+10*1u
Stosunek masowy:
mC:mH=72:10=36:5
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mC3H6=3*12u+6*1u=42u
36u---x%
42u---100%
x=85,71%C
mC6H10=6*12u+10*1u
Stosunek masowy:
mC:mH=72:10=36:5