Oblicz zawartość procentową (procent masowy) węgla w glicynie.
mH2NCH2COOH=5*1u+14u+2*12u+2*16u=75u
%C = (24/75)*100% = 32%
mC₂H₅NO₂=2*12u+5*1u+14u+2*16u=75u
24g /75g=0,32=32% węgla
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mH2NCH2COOH=5*1u+14u+2*12u+2*16u=75u
%C = (24/75)*100% = 32%
mC₂H₅NO₂=2*12u+5*1u+14u+2*16u=75u
24g /75g=0,32=32% węgla