Oblicz zawartość procentową (procent masowy) pierwiastków chemicznych w wodowotlenku wapnia.
wodorotlenek wapnia--->Ca(OH)₂
Ca--->40u
(OH)₂---->2*16u+2*1u=32u+2u=34u
40u+34u=74u
74u--->100%
40u-->x
x=40u*100%/74u
x=54,05%<--Ca
32u---->x
x=32u*100%/74u
x≈43,2%<---O
74u---->100%
2u------>x
x=2u*100%/74u
x≈2,7%<---H
liczę na naj ;d
Ca(OH)2
Ca - 1 x 40u = 40u
O - 2x 16u = 32u
H - 2x 1u = 2u
40u + 32u + 2u = 74u
wapń:
74u - 100%
40u - x
x = 54,05%
tlen:
32u - x
x = 43,24%
wodór:
2u - x
x = 2,7%
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wodorotlenek wapnia--->Ca(OH)₂
Ca--->40u
(OH)₂---->2*16u+2*1u=32u+2u=34u
40u+34u=74u
74u--->100%
40u-->x
x=40u*100%/74u
x=54,05%<--Ca
74u--->100%
32u---->x
x=32u*100%/74u
x≈43,2%<---O
74u---->100%
2u------>x
x=2u*100%/74u
x≈2,7%<---H
liczę na naj ;d
Ca(OH)2
Ca - 1 x 40u = 40u
O - 2x 16u = 32u
H - 2x 1u = 2u
40u + 32u + 2u = 74u
wapń:
74u - 100%
40u - x
x = 54,05%
tlen:
74u - 100%
32u - x
x = 43,24%
wodór:
74u - 100%
2u - x
x = 2,7%